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Topic ugh math problem
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Original Post
kruger07 Posted at 4:14 pm on July 6, 2009
how the fuck do you do standard form?

like; bc i cant grasp things easily.

:/ theres one that says

y= 5/9 x + 4

my headhurts
theres an exam tomorrow and


ughhh.

Replies
Just Waiting Here Posted at 5:00 pm on July 6, 2009
Quote: from Shush at 4:35 pm on July 6, 2009

Quote: from Just Waiting Here at 4:32 pm on July 6, 2009

For standard forms, you basically want to put everything on the same time while also getting rid of any fractions.  

 You currently have 5/9x... to make this no longer a fraction, you need to multiply both sides of the equation by 9.  

 9*(y)= (5/9 x + 4)*9  
 9y = 5x + 36  

 You no longer have any fractions left, so it's a matter of taking everything on to one side of the equation.  I personally like the 'x' to have a positive sign, so I would subtract 9y from both sides (or move 9y to the other side).  

 0 = 5x - 9y + 36



That's general form.

I'm confused, the majority of the things that I've seen have said Ax + By = C, in which case I just need to move my 36 to the other side.

However, I'm not sure what you're claiming standard form to be, because just moving x to the other side is not standard form either.  You need integers, and I believe that the coefficient of x is typically said to be a positive integer.

Shush Posted at 4:35 pm on July 6, 2009
Quote: from Just Waiting Here at 4:32 pm on July 6, 2009

For standard forms, you basically want to put everything on the same time while also getting rid of any fractions.

You currently have 5/9x... to make this no longer a fraction, you need to multiply both sides of the equation by 9.

9*(y)= (5/9 x + 4)*9
9y = 5x + 36

You no longer have any fractions left, so it's a matter of taking everything on to one side of the equation. I personally like the 'x' to have a positive sign, so I would subtract 9y from both sides (or move 9y to the other side).

0 = 5x - 9y + 36



That's general form.
Just Waiting Here Posted at 4:32 pm on July 6, 2009
For standard forms, you basically want to put everything on the same time while also getting rid of any fractions.

You currently have 5/9x... to make this no longer a fraction, you need to multiply both sides of the equation by 9.

9*(y)= (5/9 x + 4)*9
9y = 5x + 36

You no longer have any fractions left, so it's a matter of taking everything on to one side of the equation.  I personally like the 'x' to have a positive sign, so I would subtract 9y from both sides (or move 9y to the other side).

0 = 5x - 9y + 36

blitzerdog Posted at 4:31 pm on July 6, 2009

That's already in standard form. Slope/y-intercept form

Or you just do
Ax+by=C

get constant on one side, and variables on other.

TheClassic Posted at 4:30 pm on July 6, 2009
Post from this position was omitted due to content violations
Shush Posted at 4:20 pm on July 6, 2009
Quote: from TheClassic at 4:18 pm on July 6, 2009

Standard Form is y = mx + b.
So if it's y = 5/9x + b it's already standard form...


No. That's slope-intercept form.
NZ Guy Posted at 4:19 pm on July 6, 2009
What is standard form? I spent 5 years at high school (until the end) and i have only ever heard of Standard form on here, we must call it something else over here.
TheClassic Posted at 4:18 pm on July 6, 2009
Standard Form is y = mx + b.
So if it's y = 5/9x + b it's already standard form...
RubberTrees Posted at 4:18 pm on July 6, 2009
Do you mean Ax + By = C?

Edit:  What kind of problems are you doing?

LiveForeverDieTonite Posted at 4:18 pm on July 6, 2009
Ax + By + C = 0
-5x + 9y - 45 = 0

or

Ax + By = C
-5x + 9y = 45

Shush Posted at 4:16 pm on July 6, 2009
Just move the x to the left side.
LiveForeverDieTonite Posted at 4:15 pm on July 6, 2009
Post from this position was omitted due to content violations
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